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par(mfrow = c(1
2))
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120,766 skills indexed with the new KISS metadata standard.
2))
data = df)
df$%s
df$%s
] # drop rows with any NA
main = Distribution of %s
dim(df)
stringsAsFactors = FALSE)
_analysis.R)
.csv)
outcome = score
cols = n_col)
n_dup / n_row * 100))
lbl
n_lv - top_n_levels))
1)
col
n_lv)
useNA = no)
function(x) is.factor(x) | is.character(x))]
mean(x)
───
is.numeric)]
Min